Ex 11.3, 14 - Chapter 11 Class 11 Conic Sections (Term 2)
Last updated at Feb. 6, 2020 by Teachoo
Last updated at Feb. 6, 2020 by Teachoo
Transcript
Ex 11.3, 14 Find the equation for the ellipse that satisfies the given conditions: Ends of major axis (0, ± √5) , ends of minor axis (±1, 0) Given ends of Major Axis (0, ± √5), & ends of Minor Axis (±1, 0) Major axis is along the y-axis So, our required equation of ellipse is 𝒙^𝟐/𝒃^𝟐 + 𝒚^𝟐/𝒂^𝟐 = 1 We know that End of major axis is the vertices of the ellipse So vertices of ellipse = (0, ± √5) Also, Vertices of the ellipse is (0, ± a) Comparing (0, ± a) = (0, ± √5) a = √𝟓 We know that End of minor axis = (± b, 0) So, (±1, 0) = (± b, 0) So, b = 1 Required equation of ellipse is 𝑥^2/𝑏^2 + 𝑦^2/𝑎^2 = 1 Putting values 𝑥^2/1^2 + 𝑦^2/(√5)^2 = 1 𝒙^𝟐/𝟏 + 𝒚^𝟐/𝟓 = 1
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